How is the "new" work around simpler than the script below? True, it offers the floor and ceiling functions as well, but I would just have three workarounds; one for the round block, one for floor, and one for ceiling. Make sense?
if <(n) > (0)> set [rounded v] to (((n) + (0.5)) - (((n) + (0.5)) mod (1))) else set [rounded v] to ((((n) - (0.5)) - (((n) - (0.5)) mod (1))) + (1)) end
Remove workaround for floor function as use case for round function
In the use cases for the round block, one entry includes "Removing the decimal from a score, without rounding up". This isn't a genuine use case for the
round () block, because the
[floor v] of () block exists. Should we remove it?
Jokebookservice1 (talk | contribs) 22:33, 1 April 2018 (UTC)