| Item # of () in () | |
(item # of [] in [ v]) | |
| Category | List |
| Type | Reporter |
| Introduced in | 3.0 |
- The correct title of this article is Item # of () in (). The Scratch Wiki uses this different title because of technical restrictions.
Item Number of () in () is a list block and a reporter block. This block reports the index in a list where an item first appears. If an item appears more than once, it reports the index of the first occurrence of that item. If the item is not in a list, it reports 0. It is one of only two reporter blocks that can be inserted into a boolean input, the other one being the Item () of () (block) block.
Example
when gf clicked delete all of [list v] add [a] to [list v] add [b] to [list v] add [c] to [list v] add [b] to [list v] say (item # of [c] in [list v]) //says 3 since c is the third item in the list say (item # of [b] in [list v]) //says 2 since the first occurrence of b in the list is in the second position say (item # of [d] in [list v]) //says 0 since d is not in the list
Workaround
This can instead be accomplished by looking at each item in a list in order and seeing if any of them equal the item being searched for:
define item # of (search term) in list
set [counter v] to (0)
set [result v] to (0)
repeat (length of [list v])
change [counter v] by (1)
if <(item (counter) of [list v])=(search term)> then
set [result v] to (counter)
stop [this script v]
end
end
or
define item # of (string) in list set [result v] to [0] if <[list v] contains (string)?> then repeat until <(item (result) of [list v]) = (string)> change [result v] by (1) end end
Related Suggestion
Some Scratchers want an operators block that reports the appearance of a string in another. Such a block would look like this:[citation needed]
(letter # of () in ():: operators)
However, it can be worked around by this code:
define letter # of (letter) in (string)
set [counter v] to (0)
set [result v] to (0)
repeat (length of (string))
change [counter v] by (1)
if <(letter (counter) of (string))=(letter)> then
set [result v] to (counter)
stop [this script v]
end
end
 Note: | Only works if the length of letter is 1. |
